by malloc47 on 2/17/13, 4:12 PM with 13 comments
by tikhonj on 2/17/13, 10:31 PM
It starts by looking at how to evaluate the simply typed lambda calculus and then going from that to a dependently typed lambda calculus. Surprisingly, the transformation is not all that complicated!
The actual code is in Haskell.
by saosebastiao on 2/17/13, 5:05 PM
by Quiark on 2/18/13, 1:30 PM
https://bitbucket.org/quiark/hsc
The whole purpose of that mental gymnastics was to learn x86 assembly while practicing my Haskell ;)
by huhsamovar on 2/17/13, 11:39 PM
I think I'll save myself the wasted time and just use X from the get-go.
by Raphael on 2/17/13, 7:08 PM