by definetheword on 11/25/20, 12:31 AM with 143 comments
by martey on 11/25/20, 6:03 AM
> One former employee, who spoke on condition of anonymity due to their nondisparagement and nondisclosure contracts, acknowledged the gulf between theory and reality. They described SpinLaunch’s prototype centrifuge as a relatively unsophisticated machine that “any average engineering team could put together.” The employee said that scaling up to a functional suborbital launcher is going to be “very challenging” with SpinLaunch’s resources. The employee also cited the inexperience of some of the leaders. “The foresight to predict many of the issues that are going to happen was definitely lacking,” they said.
by DennisP on 11/25/20, 1:31 AM
Fuel is a minor portion of launch cost. SpinLaunch is saving fuel but throwing away rockets; it's going to be hard to compete with someone who throws away more fuel but saves the rockets.
by ogre_codes on 11/25/20, 4:13 AM
These kind of forces are pretty insane compared to even the high G boost you get on a normal rocket launch. I wonder if that is going to put a crimp on their potential client list.
by hirundo on 11/25/20, 3:10 AM
2. Use it continually to arbitrage energy prices. Buy low sell high.
3. At launch time divert the rotational energy to the centrifuge. (I'd like to see that clutch.)
4. Profit
by nohat on 11/25/20, 2:26 AM
by sneak on 11/25/20, 1:22 AM
That's gotta be one hell of a fairing.
by supernova87a on 11/25/20, 3:31 AM
Although, I guess for something about to go 5000 mph through the atmosphere, a little extra air probably isn't a big deal.
Maybe the hatch cares though.
by jl2718 on 11/25/20, 3:37 PM
The Mach angle is going to be extremely tight, so the profile of a normal spacecraft design would look like a flat plate at that speed. Normally, the craft is designed with a body shape roughly matching the Mach angle, but that would make it look like a long needle and you’d never be able to spin that up.
So instead, you can use a hypersonic projectile to open up the pressure envelope in front of the payload. This would be a big chunk of tungsten in a tear-drop shape. In this case, the shape is not for laminar aerodynamics; it’s for keeping mass in front for positive ballistic coefficient, and maintaining the same shape as it erodes. This is required because it has to stay ahead of the payload. Of course you can also make a train of these increasing in width and spaced to match the pressure cone.
The calculation for how much energy this takes is the sum of: 1. Mass to orbit. 2. The atmospheric pressure times the atmospheric height times the area of the Mach cone. 3. Heat losses. We can compute minimum values for the first two to get an idea of how much energy is required. I’m not sure about heat losses, but I think it’s roughly half the energy budget.
Overall I’d naively expect this to end up being more efficient than carrying fuel to orbit.
by mhandley on 11/25/20, 11:51 AM
by mabbo on 11/25/20, 3:19 PM
Air resistance is a function of the velocity squared and the air density. Air density is a non-linear function as well- it gets very thick near the ground.
To put all your energy into maximizing your speed while you're at ground level (the spin launcher) you're wasting huge amounts of energy just pushing air out of the way. At hypersonic speeds, you'
Rockets, by contrast, go their slowest at ground level and continually accelerate as they get higher. In SpaceX launches, they actually have a period where they throttle back as they go through "Max-Q", the highest aerodynamic pressure point, as it's more efficient to be slower until you're past this point.
I guess using electrical energy, which is a much cheaper source than chemicals like rocket fuel, makes the payoff worthwhile? I dunno, I'm skeptical.
Oh also you can only launch this somewhere that no one around will mind an insane sonic boom at ground level.
by ganonm on 11/25/20, 9:49 AM
by bob1029 on 11/25/20, 10:35 AM
Perhaps instead of directly spinning the object up to speed and "letting go", you could build up all of the energy into a heavy rotating mass which then imparts it into the spacecraft over a slightly longer timeframe via some simple mechanical clutch and cable arrangement. You would still have very strong g-forces, but you could control the impulse curve over time to spread out the forces better.
Steel cables, flywheels and other members aren't going to care about such forces as much as the delicate electronics on board a spacecraft. Let these parts do the heavy lifting and then transmit the energy into the spacecraft in a methodical manner. You need to decouple the extreme nature of this sort of energy storage system from the spacecraft until it is go time.
by beervirus on 11/25/20, 1:30 AM
Sounds like this solves the easy part (getting to high altitude), but makes the hard part (getting to orbital velocity) even harder.
by ivirshup on 11/25/20, 4:19 AM
by andrewflnr on 11/25/20, 5:03 AM
by ahaferburg on 11/26/20, 9:43 AM
Or do they somehow counter the spinning of the tether, so that the rocket's orientation remains static? If there's another bearing at the attachment point, I don't see how just the outer bearing would withstand the friction at 10000g.
by black6 on 11/25/20, 2:35 AM
by baltbalt on 11/25/20, 11:13 AM
by rcgorton on 11/27/20, 7:44 PM
by elihu on 11/25/20, 5:54 AM
by jccalhoun on 11/25/20, 3:33 PM
by JoeAltmaier on 11/25/20, 8:20 PM
by basicplus2 on 11/25/20, 6:29 AM
by mensetmanusman on 11/25/20, 12:40 PM
by absolutelyrad on 11/25/20, 4:14 AM
by Jemm on 11/25/20, 1:38 PM
by mlindner on 11/25/20, 9:05 AM
by raphar on 11/25/20, 7:47 PM
by b34r on 11/25/20, 5:33 AM